If you go to sc and slide to filter you’ll find one that solves the problem
3: terms/ 12, 8r, -3, s, -5, 15t coefficients/ 8r, 1s, 15t
One way to capture the domain of integration is with the set
Then we can write the double integral as the iterated integral
Compute the integral with respect to .
Compute the remaining integral.
We could also swap the order of integration variables by writing
and
and this would have led to the same result.
3.23 x 10^12...basically, u start at the decimal and count 12 spaces to the right
3.230000000000...now remove the decimal 3,230,000,000,000