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erastovalidia [21]
3 years ago
10

Assuming that a 90° arc has an exact length of , find the length of the radius of the circle.

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0
If the exact length is s, you have
.. s = r*θ . . . . θ = π/2
.. r = s/θ
.. r = 2s/π

Fill in the exact length for "s" in the formula and compute to find the radius.
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Is this answer correct?
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Step-by-step explanation:

yes the answer is correct

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PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
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Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let the 2 parts be x and (20 - x).

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Finding the derivative):

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So the 2 numbers are 13 1/3 and  6 2/3.

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