#1
The two functions are:

and

so the difference is that -2. Adding or subtracting a constant moves a function up (if the constant is positive) or down (if the constant is negative). So adding -2 means the function will shift down 2 units. That is, the last choice given.
#2
The horizontal distance the rocket travels is given by x. As the rocket is launched and travels a parabolic path up into the sky and back down it moves a certain distance (horizontally) away from where it started. The rocket stops traveling when it hits the ground (when the height y is equal to 0). Therefore, we are being asked to find x when y = 0. We are being asked to solve the equation:

. To solve this we can use the quadratic formula.
The quadratic formula is:

. We need to determine the values of a, b and c from the equation we are trying to solve. a is the coefficient (number in front of)

, b is the coefficient of x and c is the constant (the number by itself). So in this problem we have:
a=-.06
b=9.6
c=5.4
We need to plug these values into the formula and simplify. Since we are rounding to the nearest hundredth (two decimal places) I would carry out your calculations to at least 4 decimal places and then round at the end. This reduces errors due to rounding. Here is how we use the formula:



Before we continue we need to recognize that our answer, being a distance, has to be positive. So even though there are two solutions to the equation only the positive one is correct. We arrive at this answer as follows:
<span>(-9.6-9.6672643)/-.12=160.56
c)
</span>This part is done the same way as part b. Again, the horizontal distance the rocket travels is given by x. As the rocket
is launched and travels a parabolic path up into the sky and back down
it moves a certain distance (horizontally) away from where it started.
The rocket stops traveling when it hits the ground (when the height y is
equal to 0). Therefore, we are being asked to find x when y = 0. We are
being asked to solve the equation:

.
To solve this we can use the quadratic formula.
The quadratic
formula is:

. We need to determine the values of a, b and c from the equation
we are trying to solve. a is the coefficient (number in front of)

, b is the coefficient of x and c is the constant (the
number by itself). So in this problem we have:
a=-.02
b=.8
c=37
We
need to plug these values into the formula and simplify. Since we are
rounding to the nearest hundredth (two decimal places) I would carry out
your calculations to at least 4 decimal places and then round at the
end. This reduces errors due to rounding. Here is how we use the
formula:



Before
we continue we need to recognize that our answer, being a distance, has
to be positive. So even though there are two solutions to the equation
only the positive one is correct. We arrive at this answer as follows:
<span>(-.8-1.8973)/-.04=67.43</span>