An arithmetic progression has first term 11 and Fourth term 32. Fine the sum of the first nine term
2 answers:
Answer:351
Step-by-step explanation:Try to plus the same number every time, I used 7 and it worked. : )
Let the first term be a, 4th term be , difference between terms be d, and sum of first nine terms be .
= a + 3d
32 = 11 + 3d
3d = 32 - 11
3d = 21
d = 7
=
=
= 9(11+28)
= 9(39)
= 325
Sum of first nine terms is 351.
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