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stellarik [79]
2 years ago
13

An arithmetic progression has first term 11 and Fourth term 32. Fine the sum of the first nine term

Mathematics
2 answers:
bonufazy [111]2 years ago
6 0

Answer:351

Step-by-step explanation:Try to plus the same number every time, I used 7 and it worked. : )

schepotkina [342]2 years ago
4 0

Let the first term be a, 4th term be a_{4}, difference between terms be d, and sum of first nine terms be S_{9}.

a_{4} = a + 3d

32 = 11 + 3d

3d = 32 - 11

3d = 21

d = 7

S_{9} = \frac{9}{2} (2a + (9-1)d)

   = \frac{9}{2} (22+56)

   = 9(11+28)

   = 9(39)

   = 325

Sum of first nine terms is 351.

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<h2>7/130</h2>

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Using set notation to answer the question. let:

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3 0
3 years ago
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