![\text{Answer: }1\frac{23}{40}\ miles\text{ far she live from school.}](https://tex.z-dn.net/?f=%5Ctext%7BAnswer%3A%20%7D1%5Cfrac%7B23%7D%7B40%7D%5C%20miles%5Ctext%7B%20far%20she%20live%20from%20school.%7D)
Explanation:
Since we have given that
Speed at which Eugene walked all the way to school = 3 mph
After realizing that she forgot her math book, she ran back
Speed at which Eugene walked back to her house = 7 mph
Let the distance between her house and her school be x
According to question,
![\frac{x}{3}+\frac{x}{7}=\frac{45}{60}\\\\\frac{7x+3x}{21}=\frac{3}{4}\\\\\frac{10x}{21}=\frac{3}{4}\\\\x=\frac{3\times 63}{4\times 10}=\frac{63}{40}=1\frac{23}{40}\ miles.](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%2B%5Cfrac%7Bx%7D%7B7%7D%3D%5Cfrac%7B45%7D%7B60%7D%5C%5C%5C%5C%5Cfrac%7B7x%2B3x%7D%7B21%7D%3D%5Cfrac%7B3%7D%7B4%7D%5C%5C%5C%5C%5Cfrac%7B10x%7D%7B21%7D%3D%5Cfrac%7B3%7D%7B4%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B3%5Ctimes%2063%7D%7B4%5Ctimes%2010%7D%3D%5Cfrac%7B63%7D%7B40%7D%3D1%5Cfrac%7B23%7D%7B40%7D%5C%20miles.)
Hence,
![1\frac{23}{40}\ miles\text{ far she live from school.}](https://tex.z-dn.net/?f=1%5Cfrac%7B23%7D%7B40%7D%5C%20miles%5Ctext%7B%20far%20she%20live%20from%20school.%7D)
<span><span><span>2x</span>+3</span>=<span><span>
[email protected]</span><span>x=6</span></span></span><span><span><span><span>(2)</span><span>(6)</span></span>+3</span>=15</span><span><span>15=</span><span>15</span></span>
Answer:
1 Expandir.
-28=-21x-28+21x
−28=−21x−28+21x
2 Simplifica -21x-28+21x−21x−28+21x a -28−28.
-28=-28
−28=−28
3 Ya que ambos lados son iguales, hay infinitas soluciones.
Soluciones Infinitas
Step-by-step explanation:
Answer:
512 student tickets.
Step-by-step explanation:
Let x be number of student tickets and y be number of adult tickets.
We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:
![x+y=1294...(1)](https://tex.z-dn.net/?f=x%2By%3D1294...%281%29)
We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,
![5x+8(1294-x)=8,816](https://tex.z-dn.net/?f=5x%2B8%281294-x%29%3D8%2C816)
![5x+10352-8x=8,816](https://tex.z-dn.net/?f=5x%2B10352-8x%3D8%2C816)
![-3x+10352=8,816](https://tex.z-dn.net/?f=-3x%2B10352%3D8%2C816)
![-3x=8,816-10352](https://tex.z-dn.net/?f=-3x%3D8%2C816-10352)
![-3x=-1536](https://tex.z-dn.net/?f=-3x%3D-1536)
![x=\frac{-1536}{-3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1536%7D%7B-3%7D)
Therefore, 512 student tickets were purchased at Fridays football game.
P(A) =0.54
P(B)= 0.68
P'(A)= 1-0.54 = 0.46
P'(B)= 1- 0.68 = 0.32
The probability of neither of both event will occur:
= P'(A)×P'(B)
=0.46 × 0.32
=0.1472