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andreev551 [17]
3 years ago
11

Which element has the most favorable (most negative) electron affinity?

Chemistry
1 answer:
viva [34]3 years ago
5 0
The answer is B. Hope this helps

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How is salt water classified?
docker41 [41]
Salt water is considered a compound since water is H20 (conpound) and Salt with is NaCl.
4 0
4 years ago
When agno3 was added to test tube d it reacted with cl to form agcl precipitate. Did this result in a shift to the right or the
AlekseyPX

Answer:

Reaction will move rightwards.

Explanation:

Hello there!

In this case, according to the proposed question, it turns out possible for us to  figure out the effect of the addition of silver nitrate, by using the following representative equation for the formation of the silver chloride precipitate:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)

Now, due to the addition of silver nitrate, we will be actually adding silver ions to the solution, which means that, in terms of the Le Ch atelier's principle, the reaction will shift to the right towards the formation of more silver chloride precipitate.

Best regards!

4 0
3 years ago
On August 4, 2020, an explosion estimated at 1.2 kilotons of TNT (dynamite) destroyed
inessss [21]

Answer:

it will take that explosin 15.34 millisecond

Explanation:

as the speed is 767 and distance is 50 so time will be 767/50=15.34milliseconds

4 0
4 years ago
What is the pH of a solution with [H+]2.3 x 10^-9 ? <br> a. -9.00B.-8.64C. 9.00D.8.64?
Assoli18 [71]

pH can be defined as negative logarithm of hydronium ion concentration .

pH can be mathematical represented as :

pH =-log [H+]

[H+]=2.3*10^-9

pH= -log[2.3*10^-9]

=8.64

5 0
4 years ago
Read 2 more answers
Be sure to answer all parts. for each reaction, find the value of δso. report the value with the appropriate sign. (a) 3 no2(g)
Maurinko [17]

Answer:

Change in entropy for the reaction is

ΔS° = -268.13 J/K.mol

Explanation:

To calculate the change in entropy for the balanced reaction, we require the natural entropy of all the reactants and products in the reaction.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

From Literature.

S°(NO₂) = 240.06 J/K.mol

S°(H₂O) = 69.91 J/K.mol

S°(HNO₃) = 155.60 J/K.mol

S°(NO) = 210.76 J/K.mol

These are the entropies of the reactants and products under standard conditions of 298.15 K and 1 atm.

Note that

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

Σ nᵢS°(for products) = [2 × S°(HNO₃)] + [1 × S°(NO)]

= (2 × 155.60) + (1 × 210.76) = 521.96 J/K.mol

Σ nᵢS°(for reactants) = [3 × S°(NO₂)] + [1 × S°(H₂O)]

= (3 × 240.06) + (1 × 69.91) =790.09 J/K.mol

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

ΔS° = 521.96 - 790.09 = -268.13 J/K.mol

Hope this Helps!!

4 0
4 years ago
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