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NikAS [45]
3 years ago
13

What is The atomic mass number of tin

Chemistry
2 answers:
Svetlanka [38]3 years ago
7 0

Answer:

50

Explanation:

the atomic mass number of tin is 50

san4es73 [151]3 years ago
3 0

Answer:

50

Explanation:

The atomic number is 50

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Which of the following equilibrium systems most favors the products?
ololo11 [35]
The correction is D. This is because, the higher the value of K, the greater the relative amount of product present at equilibrium.
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What is the name of tetranitrogen dichloride?
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Not sure good luck on finding someone too help you
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3 years ago
10) A student’s calculation w as found to have a 15.6% error, and the actual value w as determined to be 25.7 mL. W hat are the
goblinko [34]

Answer:

The actual value = 25.7 ml

The error = 15.6%

This means that the value of error = 0.156 * 25.7 = 4.0092 ml

Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.

This means that the two possible readings are:

either : 25.7 + 4.0092  = 29.7092 ml

or : 25.7 - 4.0092  = 21.6908 ml

Explanation:

7 0
3 years ago
Balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl​
Mumz [18]

Answer:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

Explanation:

The products of this reaction are given by:

K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)

The following steps should be taken:

  • balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)

  • balance oxygen atoms by adding 7 water molecules on the right:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the hydrogen atoms by adding 14 protons on the left:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

Similarly, tin(II) cation becomes tin(IV) cation:

Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-

Add them together:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)

Adding the ions spectators:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

7 0
3 years ago
A 64.4-g sample of potassium chloride was added to 200.0 g of water at 20 degrees C. Is the solution saturated, unsaturated, or
Tomtit [17]
Hey there!:

is the solution <span>saturated  , ie :

</span>They are the ones that have reached the exact solubility coefficient.<span>If we mix 64.4 g of KCl at 200.0 g of water at 20 º C, we'll see that the 32.2 g will dissolve and the remainder (32.2 g) will precipitate, forming the bottom body. In this case we will then have a solution saturated with background. However, if we want only the saturated solution, simply perform a simple filtration to separate the precipitate from the saturated solution.

hope this helps!</span>
7 0
3 years ago
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