Question

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.0 gal tank (1us gal=3.78l)?

Answer 1

Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.

Since, 1 US gal=3.78 L

Volume of tank in L will be:

$V=13.0 gal(\frac{3.78 L}{1 gal})=49.14 L$

Also, 1 L=1000 mL

Thus,

$V=49.14 L(\frac{1000 mL}{1 L})=49140 mL$

Mass of gasoline can be calculated as follows:

m=d×V

Here, d is density and V is volume thus,

$m=0.737 g/mL\times 49140 mL=3.62\times 10^{4}g$

Therefore, mass of gasoline will be $3.62\times 10^{4}g$.