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3 years ago

11

Will mark brainliest! Please hurry if you can! :))

2 answers:

givi [52]3 years ago

5 0

The problem gives you the formula for the volume of a cone - you just need to find the values for the variables. In this case, we can see $h = 6$ and $r = 5$ . Thus, by using the formula with $\pi \approx 3.14$ , we can solve for the volume $V$ :

$V \approx \dfrac{1}{3} (3.14) (5^2) (6)$

$V \approx 157$

The volume is approximately 157 ft.

Verizon [17]3 years ago

3 0

Answer:

The answer is 157

Step-by-step explanation:

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Find the ordinary interest on a loan of $11,000.00 at 7.0% annually for 92 days.

Lisa [10]

someone hurry i also need help on this question!

3 0

3 years ago

Assume Y=1+X+u, where X, Y, and u=v+X are random variables, v is independent of X; E(v)=0, Var(v)=1, E(X)=1, and

kobusy [5.1K]

Answer:

a) $E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1+$

b) $E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

c) $E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

d) $E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

e) $E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

f) $E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

g) $E(u) = E(v) +E(X) = 0+1=1$

h) E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

Step-by-step explanation:

For this case we know this:

$Y = 1+X +u$

$u = v+X$

with both Y and u random variables, we also know that:

$[tex] E(v) = 0, Var(v) =1, E(X) = 1, Var(X)=2$

And we want to calculate this:

Part a

$E(u|X=1)= E(v+X|X=1)$

Using properties for the conditional expected value we have this:

$E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1$

Because we assume that v and X are independent

Part b

$E(Y| X=1) = E(1+X+u|X=1)$

If we distribute the expected value we got:

$E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

Part c

$E(u|X=2)= E(v+X|X=2)$

Using properties for the conditional expected value we have this:

$E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

Because we assume that v and X are independent

Part d

$E(Y| X=2) = E(1+X+u|X=2)$

If we distribute the expected value we got:

$E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

Part e

$E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

Part f

$E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

Part g

$E(u) = E(v) +E(X) = 0+1=1$

Part h

E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

8 0

3 years ago

Solve for a triangle. 2x + 4x + 6x = 180

a_sh-v [17]

Answer:

x=15

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Andrei [34K]

$\text{Hey there!}$

$\dfrac{330}{6}=330\div6\rightarrow\text{55}$

$\boxed{\boxed{\text{Answer: 55 was Mark's average speed}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

4 0

3 years ago

Read 2 more answers

A cone with volume 448 m^3 is dilated by a scale factor of 1/4.The volume of the resulting cone is ___ cubic meters.

stira [4]

EXPLANATION

If the volume of the cone is of V=448m^3 and it is dilated by a scale factor of 1/4, the resulting volume would be as shown as follows:

$\text{Volume}_{\text{dilated}}=448\cdot1\frac{1}{4}=560m^3$

3 0

1 year ago