Answer:
2e+13
Step-by-step explanation:
Answer:
91
Step-by-step explanation:
273 divded by 3
He can go 1 1/2 days before they are all gone
Answer:
A = 15u²
Step-by-step explanation:
Area of a Trapezoid Formula:

Plug in our values (h = 3, b1 = 7, b2 = 3)

Now we evaluate


Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³