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3 years ago

9

6(2x-1) over 5. I need help so help me pleeease

1 answer:

pav-90 [236]3 years ago

3 0

Answer:

(12x - 6)/5

Step-by-step explanation:

6(2x-1)/5 => (12x - 6)/5 because of the distributive property.

You cannot simplify farther after you reach (12x - 6)/5.

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3 years ago

Let f(x)=x^2+6x−16.<br> Enter the x-intercepts of the quadratic function in the boxes.

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$\underline{\underline{\large\bf{Given:-}}}$

$\red{\leadsto}\:$ $\textsf{}$ $\sf f(x)= x^2+6x−16$

$\underline{\underline{\large\bf{To Find:-}}}$

$\orange{\leadsto}\:$ $\textsf{ x-intercepts of the quadratic function }$ $\sf$

$\\$

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ x- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

$\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x=2\quad or \quad x=-8 \\\end{gathered}$

$\leadsto$ x-intercepts of the given quadratic function are 2 and -8 .

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