Answer:
Step-by-step explanation:
The fifth graders were given sandwiches for lunch during their field trip. Nathan ate 5/6 of his sandwich, Leroy ate 7/8 of his sandwich, and Sofia ate 5/8 of her sandwich. Who ate the greatest amount of their sandwich? ... Nathan ate 20/24, Leroy ate 21/24, and Sofia ate 15/24 meaning Leroy ate the most.
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job
We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)
We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability
P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate
Convert this to a percentage to get roughly 36.67% and this rounds to 37%
Final Answer: 37%
100%/x%=75/15
<span>(100/x)*x=(75/15)*x - </span>we multiply both sides of the equation by x
<span>100=5*x - </span>we divide both sides of the equation by (5) to get x
<span>100/5=x </span>
<span>20=x </span>
<span>x=20</span>
It’s 90 degrees sorry if I’m wrong
