This is the last answer because if you reflect it 4 times over the x and y axis you will get back to the same spot
Answer:
t=1
Step-by-step explanation:
7t-8t+4=5t-2
-1t+4=5t-2
-1t+6=5t
6=6t
1=t
Check
7t-8t+4=5t-2
7(1)-8(1)+4=5(1)-2
-1+4=5-2
3=3
Answer: A
Step-by-step explanation:
c - 12 > -16
c > -4
A
Answer: The answer would be -3
Step-by-step explanation:
<em> Subtract -4 from -1 to get your answer.</em>
The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
