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olga_2 [115]
4 years ago
15

Simplify each expression

Mathematics
1 answer:
Stells [14]4 years ago
3 0
Alright now combine all like terms remember no matter what you can allways add like terms ok now it would be 5-3 you should get two now add the n and the squared 2 and 2n2 should be your answer witch is A Now for the other equation 8+-4 =4 3b +6b = 9b now drag the 2c down and you get 4+9b-2c I hope this helps you
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3 years ago
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kumpel [21]

Answer:

Part 1) sin(\theta)=\frac{2}{3}

Par 2) cos(\theta)=-\frac{\sqrt{5}}{3}

Part 3) tan(\theta)=-\frac{2\sqrt{5}}{5}

Step-by-step explanation:

step 1

Find the sin(\theta)

we have

csc(\theta)=\frac{3}{2}

Remember that

csc(\theta)=\frac{1}{sin(\theta)}

therefore

sin(\theta)=\frac{2}{3}

step 2

Find the cos(\theta)

we know that

sin^{2}(\theta) +cos^{2}(\theta)=1

we have

sin(\theta)=\frac{2}{3}

substitute

(\frac{2}{3})^{2} +cos^{2}(\theta)=1

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cos^{2}(\theta)=1-\frac{4}{9}

cos^{2}(\theta)=\frac{5}{9}

square root both sides

cos(\theta)=\pm\frac{\sqrt{5}}{3}

we have that

cos(\theta) < 0 ---> given problem

so

cos(\theta)=-\frac{\sqrt{5}}{3}

step 3

Find the tan(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=\frac{2}{3}

cos(\theta)=-\frac{\sqrt{5}}{3}

substitute

tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}

Simplify

tan(\theta)=-\frac{2\sqrt{5}}{5}

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8 0
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MArishka [77]

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Step-by-step explanation:

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8 0
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