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sesenic [268]
4 years ago
8

The locations, given in polar coordinates, for two ships are (8 mi, 639) and (8 mi, 1239). Find the distance between the two

Mathematics
1 answer:
Roman55 [17]4 years ago
4 0

Answer:

A. \sqrt{64}=8 miles

Step-by-step explanation:

Given two Cartesian coordinates (x_1,y_1)\&(x_2,y_2), the distance between the points is given as:

d = \sqrt{((x_1-x_2)^2+(y_1-y_2)^2)}

Converting to polar coordinates

(x_1,y_1) = (r_1 cos \theta_1, r_1 sin \theta_1)\\(x_2,y_2) = (r_2 cos \theta_2, r_2 sin \theta_2)

Substitution into the distance formula gives:

\sqrt{((r_1 cos\theta_1-r_2 cos \theta_2)^2+(r_1 sin \theta_1-r_2 sin \theta_2)^2}\\=\sqrt{(r_1^2+r_2^2-2r_1r_2(cos \theta_1 cos \theta_2+sin\theta_1 sin \theta_2) }\\= \sqrt{r_1^2+r_2^2-2r_1r_2cos (\theta_1 -\theta_2)}

In the given problem,

(r_1,\theta_1)=(8 mi, 63^0) \:and\:  (r_2,\theta_2)=(8 mi, 123^0 ).

Distance=\sqrt{8^2+8^2-2(8)(8)cos (63 -123)}\\=\sqrt{128-128cos (-60)}\\=\sqrt{64}=8 mile

The closest option is  A. \sqrt{64}=8 miles

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Among fatal plane crashes that occurred during the past 55 ​years, 415 were due to pilot​ error, 96 were due to other human​ err
azamat

Answer:

Relative frequency:

\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\

The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.

Step-by-step explanation:

We have the data for fatal plane crashes. The sum of plane crashes is

We can calculate the relative frequency as:

\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\

We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.

4 0
3 years ago
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
4 years ago
PLEASE HELP!!!!! OVER DUE!! 100 POINTS!
serious [3.7K]

Answer:

2u-1/3v = (4, -2)

Step-by-step explanation:

Given vector u and v,

v = (-6, -6)

u = (1, -2)

2*u = (2*1, -2*2) = (2, -4)

1/3*v = (1/3*-6, 1/3*-6) = (-2, -2)

So, 2u = (2, -4) and 1/3*v = (-2, -2)

We have 2u-1/3v = (2, -4) - (-2, -2) = (4, -2)

Therefore, 2u-1/3v = (4, -2)

3 0
2 years ago
Solve the following equation: -4x - 6 = 10
Dafna11 [192]
-4x - 6 = 10

To solve the equation, you will have to isolate the x. Because of the equal sign, what you do to one side, you do to the other.

-4x - 6 = 10

Do the opposite of PEMDAS. First add 6 to both sides

-4x - 6 (+6) = 10 (+6)

-4x = 10 + 6

-4x = 16

Isolate the x, divide - 4 from both sides

-4x/-4 = 16/-4

x = 16/-4

x = -4

-4 is your answer

hope this helps
7 0
3 years ago
Mrs Harris needs 2 3/4 meters of material to make a dress. How many similar dresses could she make from a roll of material, 35 m
mestny [16]
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3 years ago
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