Answer:
541.67m²
Step-by-step explanation:
Step 1
We find the third angle
Sum of angles in a triangle = 180°
Third angle = Angle V = 180° - (63 + 50)°
= 180° - 113°
Angle V = 67°
Step 2
Find the sides x and v
We find these sides using the sine rule
Sine rule or Rule of Sines =
a/ sin A = b/ Sin B
Hence for triangle VWX
v/ sin V = w/ sin W = x / sin X
We have the following values
Angle X = 50°
Angle W = 63°
Angle V = 67°
We are given side w = 37m
Finding side v
v/ sin V = w/ sin W
v/ sin 67 = 37/sin 63
Cross Multiply
sin 67 × 37 = v × sin 63
v = sin 67 × 37/sin 63
v = 38.22495m
Finding side x
x / sin X= w/ sin W
x/ sin 50 = 37/sin 63
Cross Multiply
sin 50 × 37 = v × sin 63
x = sin 50 × 37/sin 63
x = 31.81082m
To find the area of triangle VWX
We use heron formula
= √s(s - v) (s - w) (s - x)
Where S = v + w + x/ 2
s = (38.22 + 37 + 31.81)/2
s = 53.515
Area of the triangle = √53.515× (53.515 - 38.22) × (53.515 - 37 ) × (53.515 - 31.81)
Area of the triangle = √293402.209
Area of the triangle = 541.66614164081m²
Approximately to the nearest tenth = 541.67m²
2 is the base and (
![\sqrt[4][a^5 b^3]](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%5Ba%5E5%20b%5E3%5D)
) is the exponent.
the 4 is called an index and it means to fi d the fourth root of the expression under the (
![\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3]](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%5Btext%5D%29%20symbol.%5C%5Ca%20fourth%20root%20is%20a%20factor%20that%20was%20multiplied%20four%20times.%20ex%3A%202%2A2%2A2%2A2%3D16.%20the%20fourth%20root%20of%2016%20is%20two.%20%5C%5Cwhen%20you%20do%20square%20roots%2C%20you%20take%20the%20number%20representing%20the%20factor%20out%20of%20the%20radical.%20anything%20else%20that%20is%20not%20a%20square%20root%20stays%20under.%20ex%3A%20%5C%5C%28%5Btex%5D%5Csqrt%5B9%5D%5Btext%5D%29%5C%5C%28%5Btex%5D%5Csqrt%5B3%2A3%2A3%5D%5Btext%5D%29%20there%20is%20one%20set%20of%20two%203%27s%20so%5C%5C%28%5Btex%5D3%5Csqrt%5B3%5D%5Btext%5D%29%5C%5Cwith%20a%20fourth%20root%2C%20you%20look%20for%20groups%20of%20four.%20the%20symbol%20of%20that%20group%20is%20placed%20outside%20the%20radical.%20anything%20else%20stays%20in.%5C%5C%20%28%5Btex%5D%5Csqrt%5B4%5D%5Ba%5E5%20b%5E3%5D)
)
(
![\sqrt[4][a*a*a*a*a*b*b*b]](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%5Ba%2Aa%2Aa%2Aa%2Aa%2Ab%2Ab%2Ab%5D)
) there is one group of 4 a's so
(
![a\sqrt[4][a* b^3]](https://tex.z-dn.net/?f=a%5Csqrt%5B4%5D%5Ba%2A%20b%5E3%5D)
)
there really isn't anything else to do to simplify the expression
Answer:
The coordinates of A would be (-1, 2)
Step-by-step explanation:
In order to find this, use the mid-point formula.
(xA + xB)/2 = xM
In this, the xA is the x value of point A, xB is the x value of point B, and xM is the x value of M. Now we plug in the known information and solve for xA.
(xA + 5)/2 = 2
xA + 5 = 4
xA = -1
Now we can do the same using the midpoint formula and the y values.
(yA + yB)/2 = yM
(yA + 10)/2 = 6
yA + 10 = 12
yA = 2
This gives us the midpoint of (-1, 2)
Answer:
Written Below.
Step-by-step explanation:
A system of linear equations has one solution when the graphs intersect at a point. A system of linear equations has no solution when the graphs are parallel. A system of linear equations has infinite solutions when the graphs are the exact same line.
(This uses graphing.)
Sidenote: I hope this helps! :)
