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PSYCHO15rus [73]
2 years ago
5

Factoring quadratics 4x^2-13x+3=0

Mathematics
2 answers:
Sindrei [870]2 years ago
7 0
X= 3 1/2 is the answer
ozzi2 years ago
6 0

Answer:

X=3,1/4

Step-by-step explanation:

4x²-(12+1)x+3=0

or,4x²-12x-x+3=0

or,4x(x-3)-1(x-3)=0

or,(4x-1)(x-3)=0

Either,4x-1=0➡️ 4x=1

X=1/4

OR,x-3=0➡️ X=3

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(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
slavikrds [6]

Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
3 years ago
The average of students is 15 years if the age of a teacher is included their average becomes 18 years .what is the age of the t
xxTIMURxx [149]

Answer:

21; the age of the teacher

Step-by-step explanation:

15+x/2=18

Estimate - I estimated in the 20's because it only averaged up a little bit

Started with 23 and kept going until i got to my answer

21

15+21/2

36/2

18

Please mark brainliest :)

8 0
2 years ago
Read 2 more answers
Help me please!!!!!!!!!!!!!
Virty [35]

Hiiiiiii

The answer is 1 1/9

5 0
3 years ago
Read 2 more answers
Consider the following polynomial. - 2x * y ^ 5 + 3x ^ 7 - 10x ^ 3 * y ^ 6 + 8x ^ 6 + 4 Which of the following statements are tr
Salsk061 [2.6K]

Option a: polynomial has 5 terms.

Option c: The constant term is 4.

Explanation:

The polynomial is -2xy^{5} +3x^{7} -10x^{3} y^{6} +8x^{6} +4

Option a: Polynomial has 5 terms

From the polynomial, we have,

1st term = -2 x y^{5}

2nd term = 3 x^{7}

3rd term = -10 x^{3} y^{6}

4th term = 8 x^{6}

5th term = 4

Hence, the polynomial has 5 terms.

Thus, Option a is the correct answer.

Option b: The leading coefficient is -2 and the degree of the polynomial is 7.

The leading coefficient is the coefficient of the variable with the largest degree.

The degree of the polynomial can be determine by the adding the powers of the variable.

degree of 1st term = -2 x y^{5} = 1+5=6

degree of 2nd term = 3 x^{7} =7

degree of 3rd term = -10 x^{3} y^{6} =3+6=9

degree of 4th term = 8 x^{6} =6

degree of 5th term = 4 =0

Thus, from these 5 terms the highest value is 9 which is the degree of the polynomial.

The polynomial -2xy^{5} +3x^{7} -10x^{3} y^{6} +8x^{6} +4 has a largest degree of 9 and the leading coefficient is -10.

Hence, Option b is not the correct answer.

Option c: The constant term is 4.

The constant term is a term in which variable will not occur.

From the polynomial -2xy^{5} +3x^{7} -10x^{3} y^{6} +8x^{6} +4, we can see that the constant term is 4.

Hence, Option c is the correct answer.

Option d: Polynomial is in decreasing degree order

The decreasing degree order is the degree in which each term is no larger than the degree of the preceding term.

From the polynomial, we have,

degree of 1st term = -2 x y^{5} = 1+5=6

degree of 2nd term = 3 x^{7} =7

degree of 3rd term = -10 x^{3} y^{6} =3+6=9

degree of 4th term = 8 x^{6} =6

degree of 5th term = 4 =0

where the degree of the 3rd term is not less than the 4th term.

Thus, the polynomial is not in decreasing degree order.

Hence, Option d is not the correct answer.

5 0
3 years ago
Find the value of the intercept
babymother [125]

Step-by-step explanation:

<em>Hope </em><em>it</em><em> </em><em>helps</em><em> </em><em>you</em>

<em>Mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>Bra</em><em>inlist</em>

3 0
3 years ago
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