Answer:
FE = 30°
Step-by-step explanation:
arc FGC = arc FG + arc GB + arc BC
220° = 90° + arc GB + 70° . . substitute known values
60° = arc GB . . . . . . . . . . . . . subtract 160°
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External angle A is half the difference of arcs EG and GB:
30° = (1/2)(arc FE +90° -60°) . . . substitute known values
60° = arc FE + 30° . . . . . . . . . . . multiply by 2 and simplify
30° = arc FE . . . . . . subtract 30°
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The key to this problem is the relationship between external angle A and the measures of the arcs it subtends.
I think the answer would be 90 students were taken on the trip. I may be wrong, so wait for more answers to come in!
V = a * b * c
a,b,c- lengths of sides
in here a=b=c=5cm
V=5*5*5 = 125 cm^3
or
V=a^3 = 5^3 =125 cm^3