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3 years ago

Help please Geometry test

Mathematics

1 answer:

ahrayia [7]3 years ago

6 0

Step-by-step explanation:

To find x,

$21x - 9 = 117$

$21x = 126$

$x = 6$

To find arc AB,

$21(6) - 9 = 117$

To find Arc AE,

$117 + x = 180$

$x = 63$

Arc ABC,

$117 + 63 = 180$

ACE

$180 + 27 + 90 = 297$

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What conclusions can be drawn about finding the quotient in scientific notation? Check all that apply.

irga5000 [103]

Answer:

B.The exponent of the solution is –12, the difference of the original exponents.

C.The coefficient of the solution must be greater than or equal to one but less than 10.

D.The quotient is 3.0 ×

Step-by-step explanation:

7 0

2 years ago

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What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$