Question

A 14 foot ladder is leaning against a building. The ladder makes a 45 degree angle with the building. How far up the building does the ladder reach?

Answer 1

Answer:

Step-by-step explanation:

It is given that A 14 foot ladder is leaning against a building. The ladder makes a 45 degree angle with the building, then let AC=14 foot and ∠C=45°and AB be the length of the building.

Thus, using the trigonometry, we have

$\frac{AB}{AC}=sin45^{\circ}$

Substituting the given values, we get

⇒$\frac{AB}{14}=\frac{1}{\sqrt{2}}$

⇒$AB=14{\times}\frac{1}{\sqrt{2}}$

⇒$AB=14{\times}\frac{\sqrt{2}}{2}$

⇒$AB=7\sqrt{2} foot$

Thus, the length of the building will be $7\sqrt{2} foot$.

Answer 2

About 5 feet tall. I assume.