A month of the year is selected at random. What is the probability that it has 31 days or starts with the letter J

Which values of x are solutions to the inequality?

Blababa [14]

Answer:

B. $x=-210$

D. $x=-201$

Step-by-step explanation:

Given:

The inequality for 'x' is given as:

$x$

The above inequality tells us that, the value of the variable 'x' is less than -200.

-200 is a negative number. So, for a negative number, the larger the value of the number, the smaller the number is.

Example: -2 is less than -1 although 2 has a greater magnitude than 1.

Therefore, the numbers that are less than -200 are -210 and -201.

So, the values of 'x' that satisfy the given inequality are -201 and -210

Thus, the correct options are (B) and (D).

8 0

3 years ago

Share £480 in the ratio 2:3:7

aleksandr82 [10.1K]

£480

2:3:7 = 2+3+7 = 12

2
--- 0f £480 = £80
12

3
--- of £480 = £120
12

7
--- of £480 = £280
12

answer = £80 : £120 : £280

5 0

3 years ago

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydive

Firdavs [7]

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>

Let distance = s

time = t

Therefore , s = k $\times t^{2}$

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k $\times (2)^{2}$

64 = k $\times (4)$

k = $\frac{64}{4}$

k = 16 ft/ $s^{2}$

We have to find how much he will fall in 10 seconds.

s = k $\times t^{2}$

s = $16 \times 10^{2}$

s = $16 \times 100$

s = 1600 ft

3 0

3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago

There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev

Rashid [163]

Answer: 5

Step-by-step explanation:

5 0

3 years ago