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3 years ago

CAN SOMEONE PLEASE HELP ME OUT ON THIS QUESTION PLEASE!!!! I WILL GIVE BRAINLIEST!!! I HAVE TO TURN THIS IN, IN AN HOUR!!!!

Mathematics

1 answer:

Leno4ka [110]3 years ago

5 0

Answer:

A) A man is happy when eating chocolate

B) Being happy is good for heath

C) Chocolate is good for health

A B C A->B B->C (A->B) (B->C)

T T T T T T

T T F T F F

T F T F T F

F T T T T T

T F F F T F

F F F T T T

F F T T T T

F T F T F F

Step-by-step explanation:

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A television set cost $350 cash when bought on hire purchase a deposit of $35 is required followed by 12 monthly payments of $30

r-ruslan [8.4K]

Answer:

www.imsorryineedpoints.orgStep-by-step explanation:

7 0

3 years ago

M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)

Deffense [45]

Answer:

Part 1) $MD=9\ units$

Part 2) $DC=12\ units$

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

In this problem

$MD=ME=MF$ ------> is the radius of a circle inscribed inside the triangle

we have that

$MF=9\ units$

therefore

$ME=9\ units$

$MD=9\ units$

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

$MC^{2} =MD^{2}+DC^{2}$

we have

$MD=9\ units$

$MC=15\ units$

substitute

$15^{2} =9^{2}+DC^{2}$

$DC^{2}=225-81$

$DC=\sqrt{144}\ units$

$DC=12\ units$

6 0

4 years ago

3x - 6 + z (if x =9) (if z = 1 )

solmaris [256]

Answer:

hope this answer helps you dear!

8 0

3 years ago

Read 2 more answers

Suppose unattached earlobes are a dominant trait. Phil and Maggie both have unattached earlobes but their daughter, Celia, does

solong [7]

Answer:

50/50

Step-by-step explanation: you can never tell really you and the husband or wife could both have blue eyes but your baby could have brown because your great great great grandma had them.

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4 years ago

no one belongs to both math club and photography club, but the two clubs join to hold a car was. nine member of the math club an

stiv31 [10]

Since there are a total number of 15 members participating, you would divide 150 by 15 since everyone would get their fair share. Next you would multiply 10 by 9 which would result to $90 and the profit the math club received

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4 years ago