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MaRussiya [10]
3 years ago
10

PLEASE I NEED HELP ASAP! Determine if 9x2 - 42x + 49 can be the area of a square. If so, what would the value of x have to be if

the area of the square is 64 square meters?
A = s2
Explain your reasoning
Mathematics
1 answer:
Inga [223]3 years ago
4 0
9x^2 - 42x + 49 is a perfect square trinomial. It factors to (3x - 7)^2
If the area is 64m^2 set this equal to the factors and solve.
(3x - 7)^2 = 64
Take the square root of both sides.
3x - 7 = + - 8
3x - 7 = 8 3x - 7 = - 8
Add 7 to both sides.
3x = 15 3x = - 1
Divide both sides by 3.
x = 5 x = -1/3
x cannot be -1/3 because it would make the length negative.
The answer is x= 5
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Answer:

Step-by-step explanation:

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5 0
1 year ago
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
3 years ago
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