How to slove this problem in Quadratic Equation title="2 x^{2} +x-3=0" alt="2 x^{2} +x-3=0" align="absmiddle" class="latex-formula">? i cant seem to get the right answer, the back of the book says -3/2,1
1 answer:
2x² + x - 3 = 0. This is a quadratic equation of the form: ax² + b . x + c = 0, where: a = 2 b = 1 c = - 3 To find the roots (or zeros) of this quadratic equation we have to apply the following formula: x' = [- b + √(b² - 4.a.c)]/2a and x" = [- b - √(b² - 4.a.c)]/2a Replace a , b and c by their respective values in both (x' and x") x' = [-1 + √(1² - 4(2)(-3)]/2(2) and x" = [-1 - √(1² - 4(2)(-3)]/2(2) x' = [-1 + √(1+24)]/4 and x' = [-1 - √(1+24)]/4 x' = (-1+5)/4 and x" = (-1 - 5)/4 x' = 4/4 and x" = -6/4 x' = 1 and x" = - 3/2
You might be interested in
Answer:
512
Step-by-step explanation:
A circle is tangent only when y and x axis collide
Answer:
Step-by-step explanation:
The formula of an area of a square:
- side of a square
We have
Substitute:
METHOD 1:
Use
METHOD 2:
Use FOIL:
Ordered pair: (2,-3) y int is (0,-5)