How to slove this problem in Quadratic Equation title="2 x^{2} +x-3=0" alt="2 x^{2} +x-3=0" align="absmiddle" class="latex-formula">? i cant seem to get the right answer, the back of the book says -3/2,1
1 answer:
2x² + x - 3 = 0. This is a quadratic equation of the form: ax² + b . x + c = 0, where: a = 2 b = 1 c = - 3 To find the roots (or zeros) of this quadratic equation we have to apply the following formula: x' = [- b + √(b² - 4.a.c)]/2a and x" = [- b - √(b² - 4.a.c)]/2a Replace a , b and c by their respective values in both (x' and x") x' = [-1 + √(1² - 4(2)(-3)]/2(2) and x" = [-1 - √(1² - 4(2)(-3)]/2(2) x' = [-1 + √(1+24)]/4 and x' = [-1 - √(1+24)]/4 x' = (-1+5)/4 and x" = (-1 - 5)/4 x' = 4/4 and x" = -6/4 x' = 1 and x" = - 3/2
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6.4*10=64 6.4*2=12.8*10*1/2=64
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x= - 2
Step-by-step explanation:
hello :
note : the equation of the axis symmetry for the parabola : y =ax²+bx+c
when : a≠ 0 is : x=- b/2a
in this exercice : a=1 and b=10
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Option D, 40
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90 + 50 = 140
180 - 140 = 40