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2 years ago

99 POINTS!!!

Chemistry

2 answers:

seraphim [82]2 years ago

7 0

1. B. Orbital Shape

2. C. counterclockwise

3. D. Electrons enter orbitals of lowest energy first

4. C. 6

5. C. 2

6. A. Filled energy sublevels

Kitty [74]2 years ago

4 0

Hi,
Pauli exclusion principle tells you that if two electrons reside in the same orbital they will have opposite spin (1/2 and -1/2), so your answer here would be anti clockwise.
Hope this helps!

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How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56

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Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.0156

Thus,

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.0156=e^{-k\times t}$

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}$

$t = 6\times t_{1/2}$

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

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Answer:

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