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Liono4ka [1.6K]
3 years ago
15

99 POINTS!!!

Chemistry
2 answers:
seraphim [82]3 years ago
7 0

1. B. Orbital Shape

2. C. counterclockwise

3. D. Electrons enter orbitals of lowest energy first

4. C. 6

5. C. 2

6. A. Filled energy sublevels

Kitty [74]3 years ago
4 0
Hi,
Pauli exclusion principle tells you that if two electrons reside in the same orbital they will have opposite spin (1/2 and -1/2), so your answer here would be anti clockwise.
Hope this helps!
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What is an atom with 2 protons and 4 neutrons
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7 0
3 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
Are there molecules of sodium chloride within a sodium chloride crystal?
alukav5142 [94]
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6 0
3 years ago
The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of
denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

Kb=\frac{[IBH^+][OH^-]}{[IB]}

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

pOH=14-8.20=5.80

[OH^-]=10^{-5.8}=1.585x10^{-6}M

Kb=10^{-5.20}=6.31x10^{-6}

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}

Finally, we solve for the equilibrium concentration of ibuprofen:

[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0
3 years ago
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