Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Mole is the unit of amount of substances of specified elementary entities
According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation
n =pV/RT
Here given data is volume = 87.1 liters
Temperature = 74 °C means 347.15 k
Pressure = 3.5 atm
R = 0.0821
Putting this value in ideal gas equation then
n =pV/RT
n = 3.5 atm×87.1 liters / 0.0821 ×347.15 k
n = 021.65 mole
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
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Answer:
2
Explanation:
because hydrogen is a diatomic element, so it can't be just H
I believe the answer is, 97.992 calories
Answer:
ACE
Explanation:
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Upward growth: Having a specific skill or being specialized in that work would also bring growth in that division. ...
Good package: A job specialization means a person is knowing how to do that work and complete it.
Answer:
Explanation:
Hello,
STP conditions are P=1 atm and T=273.15 K, thus, the reacting moles are:
Now, the balanced chemical reaction turns out into:
Thus, the exact moles of oxygen that completely react with 0.2366 moles of sulfur dioxide are (limiting reagent identification):
Since 0.2098 moles of oxygen are available, we stipulate the oxygen is in excess and the sulfur dioxide is the limiting reagent. In such a way, the yielded grams of sulfur trioxide turn out into:
By using the ideal gas equation, one computes the volume as:
It has sense for volume since the mole ratio is 2/2 between sulfur dioxide and sulfur trioxide.
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