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olchik [2.2K]
3 years ago
11

Help! It’s for chemistry I attached a picture thank you!

Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

0.15 L

Explanation:

You need to first find the volume of the container.  You can do this by dividing the mass by the density.  This will give you the mass in mL.

5.00 kg = 5,000 g

(5,000 g)/(1.00 g/mL) = 5,000 mL

5,000 mL = 5 L

Now, find the volume the seawater will take up.

(5,000 g)(1.03 g/mL) = 4854.4 mL

4854.4 mL = 4.85 L

Subtract the two volumes to find the volume that left unfilled.

5 L - 4.85 L = 0.15 L

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The correct answer is A.

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3 years ago
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An aqueous solution of iron(II) iodide has a concentration of 0.215 molal. The percent by mass of iron(II) iodide in the solutio
Basile [38]

Answer:

6.24%

Explanation:

Molality by definition means a measurement of the number of moles of solute in solution with 1000 gm or 1Kg solvent. Notice the difference that Molarity is defined on the volume of solution and Molality on the mass of solvent.

So, An aqueous solution of iron(II) iodide has a concentration of 0.215 molal.

means 0.215 moles are present in 1 Kg of solvent.

The molar mass of Fe2I = 309.65 g / mole

mass of FeI2 = moles x molar mass

= 0.215 x 309.65

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mass % of FeI2 = mass of FeI2 x 100 / total mass

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8 0
3 years ago
Complete and balance the following acid-base reaction equation ______HNO3 + ______ Mg(OH)2 ------>
jekas [21]

Answer

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

Explanation

Given:

______HNO3 + Mg(OH)2 ------>

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Hence the complete reaction of the given equation is:

___HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + H₂O

To get the balanced equation for the acid-base reaction, 2 moles of HNO₃ will react with 1 mole of Mg(OH)₂ to produced 1 mole of Mg(NO₃)₂ and 2 moles of H₂O.

Therefore, the complete and balanced equation for the given acid-base reaction is:

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

5 0
1 year ago
Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
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6 0
3 years ago
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julia-pushkina [17]

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<h3>Further explanation</h3>

Given

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