Answer:
Step-by-step explanation:
It is a result that a matrix 
is orthogonally diagonalizable if and only if is a symmetric matrix. According with the data you provided the matrix should be
We know that its eigenvalues are 
, where 
has multiplicity two.
So if we calculate the corresponding eigenspaces for each eigenvalue we have
,
.
With this in mind we can form the matrices 
that diagonalizes the matrix so.
and
Observe that the rows of 
are the eigenvectors corresponding to the eigen values.
Now you only need to normalize each row of dividing by its norm, as a row vector.
The matrix you have to obtain is the matrix shown below
X by itself is 1, otherwise it is the number to the left
The answer is [ ∠A ≅ ∠A; A F/AB = AG/AC = 3 ]
Both triangles are the same just different sizes.
The length of A F is 9 units. The length of AB is 3 units.
To find the scale factor, just divide.
9 / 3 = 3
The length of AG is 6 units. The length of AC is 2 units.
To find the scale factor, just divide.
6 / 2 = 3
The only logical answer is B because the ratio's are written to where when you solve them, you get the scale factor 3.
Best of Luck!
Surface Area of a cylinder 2(π•r²)+(2π•r)•h
So
If the diameter is 8 then the radius is 4. the height is 5.
so you have, 2(3.14•4²)+(2•3.14•4)•5
solve. PEMDAS
Parentheses & Exponents first.
2(3.14•16)+(2•3.14•4)•5
2(50.24)+(6.28•4)•5
2(50.24)+(25.12)•5
Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm
1 and 1/2x+3/4x=5/8
combine x's
1 and 1/2x=4/4x+2/4x=6/4x
6/4x+3/4x=5/8=9/4x
9/4x=5/8
multiply both sides by 8
18x=5
x=5/18
x=5/18 or aprox 0.277777777777
