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2 years ago

6

Approximately students attend Jones Middle School. Below is the data collected from two random samples of students regarding sch

ool lunch preference. Which of the following inferences can be made based on the data collected? Select all that apply.

1 answer:

erastova [34]2 years ago

4 0

Answer:

there is nothing to select. u need to provide more info

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HEY PLEASE HELP ME ASAP I NEEEEEED HELP

maks197457 [2]

Since only half of the 8 white eggs are cracked, then there are 4 cracked, white eggs. The probability of drawing one of these 4 from the 18 total eggs is 4/18 which simplifies to 2/9 or 22%.

I hope this was quick enough haha, have a nice day and remember that Jesus loves you <3

3 0

2 years ago

Margie is standing on a bridge looking at the river below. She throws a rock over the bridge with an initial

Marina CMI [18]

<h2>Explanation:</h2><h2></h2>

Here we know that Margie is standing on a bridge looking at the river. She throws a rock over the bridge with an initial velocity of 60 ft/sec. The height, h, of the rock at the rime t seconds after it was thrown can be modeled by the equation:

$h(t) = -16t^2+60t+72$

To calculate how long will it take for the rock to reach the surface of the water, we need to set $h(t)=0$ . So:

$0 = -16t^2+60t+72 \\ \\ \\ \text{Using quadratic formula}: \\ \\ t=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ a=-16 \\ \\ b=60 \\ \\ c=72 \\ \\ \\ t=\frac{-60 \pm \sqrt{60^2-4(-16)(72)}}{2(-16)} \\ \\ t=\frac{-60 \pm \sqrt{60^2-4(-16)(72)}}{2(-16)} \\ \\ t=\frac{-60 \pm \sqrt{8208}}{-32} \\ \\ t_{1}=4.70 \\ \\ t_{2}=-0.95$

Given that time can't be negative, we just choose the positive value. Therefore, <em>it will take 4.70 seconds for the rock to reach the surface water.</em>

6 0

2 years ago

Anon25 [30]

equivalent to 5/24 is 15/72 (multiply top and bottom by 3)

answer is d. 15/72

7 0

3 years ago

Read 2 more answers

Simplify expression:<br> 3^{−(4a+1)} −3^{−(4a−1)} + 3^{−4a}

lyudmila [28]

$3^{-(4a+1)}-3^{-(4a-1)} + 3^{-4a} =3^{-4a-1 }-3^{- 4a+1 } + 3^{-4a}=\\ \\=3^{ -4a }*3^{-1}-3^{ - 4a }*3^1 + 3^{-4a} =3^{-4a}(3^{-1}-3+1)=3^{ -4a }*(\frac{1}{3}-2)=\\ \\=3^{ -4a }*(-1\frac{2}{3})=3^{ -4a }*(-\frac{5}{3})=3^{ -4a }*(-5)*\frac{1}{3} =-5 *3^{ -4a }*3^{-1}=\\ \\ =-5 *3^{ -4a +(-1)}=-5 *3^{ -4a -1}$

3 0

2 years ago

Simplify - 4 power 4 × 5 power -4

Dmitrij [34]

Answer:

4^4 * 5^-4

solution:

=4^4 * 1/5^4

=246*1/624

=246/624

=41/104

5 0

2 years ago

Read 2 more answers