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3 years ago

How many triangles can be constructed with angles measuring 80° 80° and 40°

1 answer:

6 0

None because a triangle has to equal 180 degrees and the measurements you have equal 200 degrees. So no triangles can be constructed with those measurements

You might be interested in

What to the 4th power is equal to 256?

levacccp [35]

Hey There!

The answer would be 4, this is the answer because 4*4*4*4=256

Thus, $4^{4}$ =256

Thank You!

6 0

3 years ago

There are a total of 33 patients discharged, 16 are male, what is the percentage of discharged that are male?

Alex

Answer:

94.72%

Step-by-step explanation:

I firgured out what 16% of 33 is = 5.28 and then I did 100- 5.28 and I got 94.72 which would be 94.72%

4 0

3 years ago

I Which of the following is the most appropriate unit to describe the rate at which people are entering Disneyland?

skad [1K]

Answer: D

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

It took Hiro 1/3 of an hour to run from his house to school.

kipiarov [429]

If they live at the same house and go to the same school then both, but if different house and school then with this info its impossible to know

5 0

4 years ago

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

3 years ago