Answer:
Answer: B) initial height = 150; hits the ground between 5 and 6 seconds
Equation 1 is 
,
Equation 2 is [/tex] 3x-2y = -1 [/tex]
for first equation LCD= 3 *5 = 15 , So we multiply whole equation by 15
Now multiply second equation by -3 , to make the coefficient of y equal and opposite , so that we can apply the elimination method
Add both the equations
Divide both sides by 11
Plug in any one of the equation we get
3(3) -2y = -1
9 - 2y = -1
subtract 9 from both sides
-2y = -10
divide both sides by -2
y=5
So the solution is x= 3 , y= 5
Which means
a. The system is consistent and independent. TRUE
The Answer is Triangular Prism.
2x + 2y = 6 . . . . . (1)
x + 3y = -1 . . . . . (2)
(1) x 3 => 6x + 6y = 18 . . . . . (3)
(2) x 2 => 2x + 6y = -2 . . . . . (4)
(3) - (4) => 4x = 20
x = 20/4 = 5
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
