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geniusboy [140]
3 years ago
9

I was wondering how you do the equation f (x)=6x^3+8?

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0
0=6x^3+8
-8           -8
-8=6x^3
----   ------
  6       6
(-8)/6=x^3
cube root each side to get
∛[(-8)/6]=x or F(x)=∛[(-8)/6]
F(x)=-1.100642...
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Answer:

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Hope this helps

7 0
2 years ago
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Elodia [21]

given ,

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now we know that ,

\\{Area \: of \: sector =  \frac{\theta}{360\degree}  \times \pi \: r {}^{2} } \\  \\

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

\\\dashrightarrow \:  \frac{45}{360}  \times  \frac{22}{7}  \times 12 \times 12 \\  \\ \dashrightarrow \:  \frac{1}{8}  \times  \frac{22 \times 12 \times 12}{7}  \\  \\ \dashrightarrow \:  \frac{22 \times 12 \times 12}{56}  \\  \\ \dashrightarrow \:  \frac{3168}{56}  \\  \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)

hope helpful :D

6 0
2 years ago
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Simple trial and error.
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