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NikAS [45]
3 years ago
8

The formula T = 1/f relates the period of a sound wave T to its frequency f. Solve this formula for f.

Mathematics
2 answers:
bija089 [108]3 years ago
8 0
T = 1/f 
<span>We solve for f. What we can do here is to get the reciprocal of both sides to get f: </span>
<span>reciprocal of T: 1/T </span>
<span>reciprocal of 1/f: f </span>
<span>Therefore </span>
<span>1/T = f, or </span>
<span>f = 1/T</span>
Liono4ka [1.6K]3 years ago
7 0
T=\frac{1}{f}

multiply \space\ both \space\ sides \space\ by \space\ f

Tf=1

divide \space\ both \space\ sides \space\ by \space\ T

f=\frac{1}{T}
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Jim has 48 sweets he wants to give one-third of them to his friend bob
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Answer:

16

Step-by-step explanation:

One third of 48 = 48 ÷ 3 = 16

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Could someone help me pleaseee
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Answer:

a) We are given the length of both legs. We need to find the hypotenuse.

b) 40^2 + 71.5^2 = X^2

c) 40^2 + 71.5^2 =

   1600 + 5,112.25 = 6,712.25 in.

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Step-by-step explanation:

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3 years ago
How to make a graph of an exponential function that shows exponential decay and has a y intercept of 2
Sliva [168]

Answer:

f(x)=2e^{-kx}

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Step-by-step explanation:

6 0
3 years ago
A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0
3 years ago
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