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nordsb [41]
3 years ago
10

which statement correctly defines the interquartile range for the set of data represented by the box plot A 14-1=13 , B 11-6=5,

c 11-1=10, d 6-1=5​
Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer:

The answer is B, 11-6=5

Step-by-step explanation.

Since the range of both quartiles is 11 and 6. You would subtract both of these to get the answer. Which in this case, is 5.

bezimeni [28]3 years ago
4 0

Answer:

B

Step-by-step explanation:

You might be interested in
Anyone help please....
MissTica

mean= 4.1

median= 1,2,3,4,5,6

mode= 6

Step-by-step explanation:

4 0
4 years ago
A certain book is for sale in both Belize and Brazil. In Belize, it sells for 80.39 Belize dollars. In Brazil, it sells for 63.6
bixtya [17]
A book is sold in Belize for 80.39 Belize dollars.
In Brazil, it sells for 63.65 Brazilian reals.

The exchange rate of US Dollars to Belize Dollars is 1:1.9246
<span>The exchange rate of US Dollars to Brazilian Real is 1:1.7880
</span>
If we convert the two into dollars,
Belize Dollars 
1 : 1.9246 = X : <span>80.39 
1.9246X = 80.39
X = $ 41.77 

</span>Brazilian Real
1 : 1.7880 = X : <span>63.65 </span><span> 
</span>1.7880X = <span>63.65 </span><span>
X = $ 35.60
</span>
Difference = $ 41.77 - $ 35.60
Difference = $ 6.17

So, in Belize the book is more expensive by $ 6.17
7 0
4 years ago
Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the
uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

  • If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
  • If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
  • If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
  • If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

  • If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
  • If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
  • If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
  • If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21)  - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21  nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21  over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>
  • 9.9 trillion seconds
  • 2,755,750,000 hours
  • 114,822,917 days
  • 314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0
3 years ago
if someone buys an orange for 27pounds and that person pays with 1 pound how much does that person get back
Darya [45]

Answer:

-26 pounds

Step-by-step explanation:

if something coasts 27 pounds and you give them 1 pound

27-1=26 you're short 26 pounds

therefore the answer is -26

3 0
3 years ago
I need help ASAP I will give brainliest if correct
alexdok [17]
Part 1)
we know that
the property of cyclic quadrilaterals for which opposite angles are supplementary
then
m∠A°+43°=180°------------> m∠A=180°-43°=137°

the answer is m∠A=137°


Part 2) 
<span>Quadrilateral ABCD ​ is inscribed in a circle. What is the measure of angle A?

we know that
</span>the property of cyclic quadrilaterals<span> for which opposite angles are supplementary
then:</span>
<span>m∠A+m∠C=<span>180<span>∘
(2x+9)+(3x+1)=180---------------> 5x+10=180
x=(180-10)/5=34

</span></span></span>m∠A=2x+9-------------> 2*34+9=77°
<span>
the answer is </span>m∠A=77°<span>

</span>
8 0
4 years ago
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