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2 years ago

Estimate 8,109-4,228 by first rounding each number to the nearest hundred.

Mathematics

1 answer:

HACTEHA [7]2 years ago

7 0

Answer: 8109-4228.00

Step-by-step explanation: I'm big brain

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Solve the inequalities<br><br> -7d + 8 > 29

Arisa [49]

-7d > 21
d < -3

Remember the sign flips when you multiply or divide by a negative number.

3 0

3 years ago

Solve the following systems of equations. Express your answer as an ordered pair in the format (a,b), with no spaces between the

kodGreya [7K]

Answer:

(4, 1)

Step-by-step explanation:

3x+4y=16 /*4

-4x-3y= - 19 /*3

12x + 16y = 64

7y = 7

y = 1

3x+4y=16

3x + 4*1 = 16

3x = 16 - 4

3x = 12

x = 4

4 0

3 years ago

2/5 × 6/7= simplify form

kirill115 [55]

Answer:

2 x 6 = 12

5 x 7 = 35

12/35

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

HELPP I don’t get this at all. I originally got c but my teacher said it was incorrect. This is about volume and cylinders. Expl

EastWind [94]

Answer:

Step-by-step explanation:

The formula for the volume of a cylinder is $\pi r^2 h$ , where r is the radius of the base and h is the height of the cylinder.

$\pi \cdot 3.25^2 \cdot 10=105.625\pi \text{ cm}^3$

Therefore, the correct answer is choice B. Hope this helps!

4 0

3 years ago

Read 2 more answers

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago