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Goryan [66]
1 year ago
15

A card is drawn from a pack of 52 cards. Find the probability of drawing an ace given that it is diamond.4/521/132/134/13

Mathematics
1 answer:
ICE Princess25 [194]1 year ago
8 0

Solution:

The probability of an event is expressed as

P(event)=\frac{number\text{ of desired outcome}}{number\text{ of possible outcome}}

In a pack of 52 cards, we have

\begin{gathered} number\text{ of diamonds=13} \\ number\text{ of ace= 1} \end{gathered}

Thus, we have the probability to be evaluated as

P(ace)=\frac{1}{13}

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1/10 if you divide 10 by 100 it would be 1/10
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28+56t+28w to identify the equivalent expressions.<br> Choose 2 answers:
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Answer:

28(1 + 2t + w)

Step-by-step explanation:

This polynomial can be factored by factoring out 28.

28 + 56t + 28w = 28(1 + 2t + w)

4 0
2 years ago
Solve the equation 18=n-18<br><br>n=_____​
Maksim231197 [3]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
Adult tickets to a play cost $22 tickets for kids cost $15. Tickets for a group of 11 cost a total of $228. How many children an
Zina [86]

Answer:Number of children = 2 and number of adults = 9 attended the play

Step-by-step explanation:

Step 1

Let the  number  of children be represented as  x

and the number of adults in the group  be represented as  as y

such that the total number of the group that went to the play

= x+y=11--- equation 1

And the total cost paid for the play will be expressed as

15x+  22y= 228------ equation 2

Step 2-- Solving

x+y=11--- equation 1

15x+  22y= 228------ equation 2

B y elimination method, multiply equation 1 by 15 to give equation 3  and then subtract from equation 2

15x+  22y= 228------ equation 2

15x+15Y= 165----- equation 3

7y=63

y= 63/7= 9

y= adults = 9

therefore x = number of children will be

x+y=11

x+ 9=11

x= 11-9= 2

In the group that attended the play,  Number of children = 2 and number of adults = 9

8 0
2 years ago
The probability distribution function for the discrete random variable where x is equal to the number of red lights drivers typi
Ivahew [28]

Using probability concepts, it is found that:

a) The missing value is 0.04.

b) The mean is of 0.37.

The distribution is given by:

P(X = 0) = 0.76

P(X = 1) = 0.15

P(X = 2) = 0.05

P(X = 3) = x

Item a:

The sum of <u>all the probabilities has to be 1</u>, that is:

\sum_{i = 0}^{3} P(X = i) = 1

Thus:

0.76 + 0.15 + 0.05 + x = 1

0.96 + x = 1

x = 0.04

The missing value is 0.04.

Item b:

The mean is given by the <u>sum of each outcome multiplied by it's probability</u>, thus:

E(X) = 0(0.76) + 1(0.15) + 2(0.05) + 3(0.04) = 0.37

The mean is of 0.37.

A similar problem is given at brainly.com/question/20709747

7 0
2 years ago
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