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makvit [3.9K]
2 years ago
8

You are preparing to tile the floor of a rectangular room that is 15.5 feet by 18 feet in size. The tiles you plan to use are sq

uares, measure 12 inches on each side, and are sold in boxes that contain enough tiles to cover 25 square feet.
To calculate the number of boxes you need to complete the job you multiply 15.5 by 18 and then divide by 144 to determine that you need just under 2 boxes. Is this correct?
A) Yes.
B) No, you need to multiply 18 by 2, then divide by 15.5 to determine the number of boxes.
C) No, after multiplying 15.5 by 18 you need to divide by 25 to determine the number of boxes.
D) No, after multiplying and dividing you need to multiply by 25 to determine the number of boxes.
Mathematics
1 answer:
Artemon [7]2 years ago
7 0

Answer:

C) No, after multiplying 15.5 by 18 you need to divide by 25 to determine the number of boxes.

Step-by-step explanation:

The dimensions of the rectangular room are 15.5 feet x 18 feet.  Which is a total area of:  15.5 x 18 = 279 ft².

The tiles being used are 12 inches x 12 inches or 1 foot x 1 foot.  Since there are 25 tiles in each box, it can cover an area of 25 ft ².  

When doing calculations with measurements, the measurements must be the same.  For instance, you can not divide square feet by inches because they are different measurements.  However, you can divide by square feet.  To the total square footage of the room (279 ft²) can be divided by the amount of square feet covered by each box (25 ft²):  279/25 = 11.16 or a minimum of 12 boxes would be needed.  

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14(0.89)^x+4.5 =162
lisabon 2012 [21]
14(0.89)^{x + 4.5} = 162
\frac{14(0.89)^{x + 4.5}}{14} = \frac{162}{14}
0.89^{x + 4.5} = 11\frac{4}{7}
ln(0.89^{x + 4.5}) = ln(11\frac{4}{7})
(x + 4.5)ln(0.89) = ln(11\frac{4}{7})
\frac{(x + 4.5)ln(0.89)}{ln(0.89)} = \frac{ln(11\frac{4}{7})}{ln(0.89)}
x + 4.5 = -2101.14032500
x = 2105.64032500
3 0
3 years ago
The three factors that must exist for a person to commit fraud include
Nimfa-mama [501]

Answer:

(1) Opportunity, (2) Pressure, and (3) Rationalization must exist for a person to commit fraud.

Important to Note:

Pressure is sometimes referred to as <em>motivation</em> or <em>incentive.</em>

Rationalization is sometimes called <em>justification</em> or <em>attitude.</em>

7 0
2 years ago
please help.....................................................................................................................
vitfil [10]
The range for group 2 is greater than the range for group 1
8 0
3 years ago
The ticket price for an ice hockey match used to cost £19.60. The price has now increased by 12.5%. How much will 2 tickets cost
Amanda [17]

Answer:

The 2 tickets will cost £44.10 after the increase.

Step-by-step explanation:

First, you have to multiply £19.60 by 12.5% to find the increase in the cost of tickets.

19.60(0.125)=2.45

Add the price increase to the original cost to find the new cost of each ticket.

19.60+2.45=22.05

Multiply the result by 2 since you have to look for the cost of the 2 tickets.

22.05(2)=44.10

8 0
3 years ago
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
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