Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'
It’s either volume or matter
^ is in the thousadths place so look for the number before it, which is 3. 3 is less than 5 so 6 stays as is so it becomes 1.736
Answer:
A=10506.25 Sq.yards
Step-by-step explanation:
Width of the park=85 yds
Lenght of the park=120 yds
Now,
A=L*W
A=120*85
A=10200 square yards. This is the area of your given rectangle.
Now,
P=2(L+W)
P=2(120+85)
P=2(205)
P=410 this is the perimeter of your given rectangle.
Now,
a=410/4=102.5
Now,calculate the area of newly given distance of each side:
A=a^2
A=102.5^2
A=10506.25 Sq. Yards
This is the new area and is larger than the area of the given rectangle which was 10200 square yards.
Step-by-step explanation:
1) 15/60 = 3/12 = 1/4
2) 8/36 = 4/23