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Ostrovityanka [42]
3 years ago
14

Laura is 3 times as old as Maria was when Laura was as old as Maria is now. In 2 years Laura will be twice as old as Maria was 2

years ago. How old are they now?
Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

Laura is 30 years old and Maria is 18 years old.

Step-by-step explanation:

Let x be the present age of Laura and y be that of Maria.

Laura was 3 times older than Maria when Laura had Maria's present age.

Lets say Laura had Maria's present age(y) k years before.Then Maria's age at that time will be y-k where k=(x-y).

Then:

y=3(y-k)

y=3(y-(x-y))

y=3(2y-x)

3x=5y  -------1

After two years Laura will become x+2 years old and 2 years ago Maria was y-2 years old. Then:

x+2=2(y-2)

x=2y-6--------2

Solving 1 and 2 we get:

x=30 and y=18

Hence Laura's present age is 30 and Maria's present age is 18.

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Step-by-step explanation:

The population in the study is the adult women who are 30 to 70 years of age and live in the United States. In statistics, a population is the whole or entire pool of items or event from which a statistical sample is drawn. A population may refer to an entire group of people, objects, events, church visits, food consumed or measurements. In the case above the population from which the sample was drawn is the adult women from age 30 to 70 that lived in the United States, no sample was drawn outside this population.

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Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
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======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

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-----------------

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