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nikitadnepr [17]
2 years ago
7

12 + 3 (URGENT!!!!!!)

Mathematics
2 answers:
atroni [7]2 years ago
8 0

Answer:

The answer is 15

matrenka [14]2 years ago
7 0
The answer is 15, hope it helps
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Step-by-step explanation:

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Given y = 2(x-3) and a domain of (-3,-2 and 5). Find the range.
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12. Will you miks the paint? Answers
wolverine [178]

The required proportion of the blue paint is 18 liters.

Given that,
The ratio of yellow and blue colors is 2:3
The proportion of the yellow color is 12 liters.
The proportion of blue color is to be determined.

<h3>What is the Ratio?</h3>

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

Let the proportion of the blue color is x,
Now, the ratio can be given as
12 / x = 2 / 3
x = 12 * 3 / 2
x = 18

Thus, the required proportion of the blue paint is 18 liters.

Learn more about Ratio here:

brainly.com/question/13419413

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The question given is incomplete, a proper question could be
A paint store mixes yellow and blue paint in a ratio of 2:3 to make green paint. If they used 12 liters of yellow paint, how many liters of blue paint were used?

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1 year ago
The first transformation for this composition is [________], and the second transformation is a translation down and to the righ
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Read 2 more answers
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
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