Answer: 1 ⁸/₂₁ litres
Step-by-step explanation:
First find a common multiple to enable you add them up:
= 21
21 will be the denominator.
Multiply each numerator by the number you get when you divide 21 by the denominator.
= 21/3 = 7
= 7 * 2 = 14
= 21/7 = 3
= 3 * 5
= 15
litres
Answer: a = 3∛2
<u>Step-by-step explanation:</u>
ab⁴ = 384 --> a = 384/b⁴
Substitute a = 384/b⁴ into the second equation to solve for "b".
a²b⁵ = 4608
![\bigg(\dfrac{384}{b^4}\bigg)^2\cdot b^5=4608\\\\\\\dfrac{147,456b^5}{b^8}=4608\\\\\\\dfrac{147,456}{b^3}=4608\\\\\\\dfrac{147,456}{4608}=b^3\\\\\\32=b^3\\\\\\\sqrt[3]{32} =b\\\\\\2\sqrt[3]{4} =b](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B384%7D%7Bb%5E4%7D%5Cbigg%29%5E2%5Ccdot%20b%5E5%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456b%5E5%7D%7Bb%5E8%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7Bb%5E3%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7B4608%7D%3Db%5E3%5C%5C%5C%5C%5C%5C32%3Db%5E3%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7B32%7D%20%3Db%5C%5C%5C%5C%5C%5C2%5Csqrt%5B3%5D%7B4%7D%20%3Db)
Substitute b = 2∛4 into the first equation to solve for "a".
ab⁴ = 384
a(2∛4)⁴ = 384
a = 384/(2∛4)⁴
a = 24/4∛4
= 6/∛4
= 6(∛2)/2
= 3∛2
The answer is that they will meet at 7.20 pm ! hope this helped
Answer:
Step-by-step explanation:
Let L represent the length of the triangle.
Let W represent the width of the triangle.
The length of a rectangle is four more than three times the width. This means that
L = 3W + 4
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
If the perimeter of this rectangle is at least 70 square centimeters, an inequality that can be solved to find the width of the rectangle is
2(L + W) ≥ 70
L + W ≥ 70/2
L + W ≥ 35
Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13
Exponential decay obeys the equation
where t = time, days
For half life, the mass is m = m₀/2.
Therefore
Answer: The half life is 5.33 days
