<h3>
Answer:</h3><h3>D</h3><h3 /><h3>
Step-by-step explanation:</h3><h3>
</h3><h3>In a function, an input (x) value should have only one output (y) value.</h3><h3 />
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<em>Example: (View attached image below). </em><em>Table A</em><em> is a function because each </em><em>x </em><em>value has only 1 </em><em>y</em><em> value. But </em><em>Table B</em><em> is not a function because the </em><em>x value</em><em> of </em><em>4 </em><em>has </em><em>2 y values</em><em>.</em>
Answer:
2005 points
Step-by-step explanation:
1. 35x50=750
2. 2 min. 45 sec.=(-165 sec.)
3. 500x5=2500
4. 2500-495=2005
Hope this helped!!:)
Answer:
a) 
b) 
c) Mary's score was 241.25.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a) Find the z-score of John who scored 190
b) Find the z-score of Bill who scored 270
c) If Mary had a score of 1.25, what was Mary’s score?
Mary's score was 241.25.
If the area was 16cm^2 before, then each side was 4 cm long since each side of a square is equal, and the area for a square is the length of the sides squared. The square root of 16 is 4, so that is why the sides were 4 cm. When you make each side 1 cm shorter, they're now all 3 cm. 3^2 is 9, so the new area is 9 square centimeters.
Given:
T (-3,4) ; O (-4,1) ; Y (-2,3)
T'(-1,1) ;
T
-3 move forward 2 points to reach -1
4 move forward 3 points to reach 1
O
-4 move forward 2 points to reach -2
1 move forward 3 points to reach -2
Y
-2 move forward 2 points to reach 0
3 move forward 3 points to reach 0.
O'(-2,-2) ; Y'(0,0) 1st option.
