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ad-work [718]
3 years ago
15

6.Find the equation of the line: through: (-2, 3) and (1,5)

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

y=2/3x+4.3

Step-by-step explanation:

y=mx+c

(5-3)/(1--2)

2/3= gradient

y=2/3x +c

5=2/3(1)+c

-2/3

4.3=c

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sesenic [268]

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\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

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-4/5 + 4/5<br> Please I need the grade
KATRIN_1 [288]

Answer:

0 hope it helps ok bye have a good grade

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