3 years ago

PLEASE ANSWER ASAPP I HAVE A PICTURE ATTACHED

Mathematics

2 answers:

Alik [6]3 years ago

3 0

Its c I've done this before

victus00 [196]3 years ago

3 0

Answer:

Step-by-step explanation:

just do it.

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A cake recipe requires 3 and 1/4 cups of flour for 13 servings and 4 and 1/2 cups of flour for 18 servings. How much flour is re

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So, each serving requires:

3 1/4 divided into 13:
$3\frac{1}{4} /13= \frac{13}{4} * \frac{1}{13} = \frac{1}{4}$

let's check from the second information:
4 2/4 divided into 18:
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4 years ago

Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan

Vikki [24]

Answer:

$\dfrac{17x^3-221x^2+425x-5525}{9}\\$

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hello

we need to find something like, a being real

$a(x-13)(x-5i)(x+5i)$

with a so that

$a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}$

so the third degree polynomial that we are looking for is

$\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\$

hope this helps

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