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3 years ago

ASAP please help with math thanks

Mathematics

1 answer:

fomenos3 years ago

5 0

Answer:

2: 6,8

Step-by-step explanation:

2) Look at the range from 6-8 then look at the frequency. The frequency is the highest so that is the most frequent range that they scored in.

I apologise for only answering one question. I don't have access to paper rn and this is hard stuff to do in my head.

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Two cars start from towns 700 mi apart and travel toward each other. They meet after 7 hr. Find the speed of each car if one tra

Trava [24]

Answer:

One car was going 45 mph and the other was going 55 mph

Step-by-step explanation:

7 0

4 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

How to solve the equation

Korolek [52]

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3 0

3 years ago

How do you do question 22

Alborosie

Answer:

∠YXZ = 58°

Step-by-step explanation:

Use the angle sum theorem and the given relations.

∠WXY +∠WXV = ∠YXV

∠WXY +(11° +3∠WXY) = 139°

4∠WXY = 128° . . . . . subtract 11°

∠WXY = 32° . . . . . . . divide by 4

Similarly, ...

∠WXY +∠YXZ = 90°

∠YXZ = 90° -∠WXY = 90° -32°

∠YXZ = 58°

6 0

3 years ago

If h(x) = 5 + x and k(X) =. 1/x which expression is equivalent to (kon)(x)?

VladimirAG [237]

Answer:

(5+x)/x

Step-by-step explanation:

Given

h(x)= 5+x

k(x)= 1/x

(koh)(x)=?

Here you multiply

1/x( 5+x)

5/x +x/x

5/x+1 or

5/x +x/x

(5+x)/x

8 0

4 years ago

Read 2 more answers