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-Dominant- [34]
3 years ago
15

(7x+40)+(6x+43)=180 x? Z?

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

(7x + 40) + (6x + 43) = 180\\7x + 40 + 6x + 43 = 180\\7x + 6x = 180 - 40 - 43\\13x = 97\\x = \frac{97}{13}

I'm not sure what you mean by Z but x is \frac{97}{13}

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Write <img src="https://tex.z-dn.net/?f=cot%5E%7B2%7D%20x%20%281%2Btan%5E%7B2%7D%20x%29" id="TexFormula1" title="cot^{2} x (1+ta
ASHA 777 [7]

Step-by-step explanation:

From Trig

1 + tan²x = Sec²x

Also

Sec²x = 1/cos²x

Now

Cot²x = 1/tan²x = cos²x/sin²x

Putting all together

Cot²x(1+tan²x)

= Cot²x(sec²x)

= cos²x/sin²x(1/cos²x)

cos²x on the numerator and that one the denominator cancels out

we have

= 1/sin²x

From Trig

1/sin²x = cosec²x

So Our Answer = cosec²x.

7 0
3 years ago
A legislative committee is weighing the pros and cons of a clean-air program. If it spends $1 million on the program, the air wi
Ksivusya [100]
B..
After each million spent, it decreased by 50%.. after 1 million +20% after 2 million +10% .. and so on

3 million is a lot for only 5 percent.. imo
4 0
4 years ago
Read 2 more answers
Look at the picture
IRISSAK [1]

Answer:

x = 10

Step-by-step explanation:

In the last step, you can see that the fraction \frac{1}{5} has been multiplied by its reciprocal \frac{5}{1}, making it cancel out. The reciprocal has been multiplied to both sides, so all you need to do is multiply \frac{6}{3} · \frac{5}{1} :

6 · 5 = 30

3 · 1 = 3

<u><em>So now you should have the fraction:</em></u>

x = \frac{30}{3}

<u><em>But, you can still simplify the fraction by dividing 30 by 3:</em></u>

x = 10

7 0
3 years ago
Solve for all values of x by factoring.<br><br> X^2-x+1=3
AlladinOne [14]

Answer:

x = 2, -1

Step-by-step explanation:

x² - x + 1 = 3

         - 3  -3

x² - x - 2 = 0

(x -2)(x + 1)

3 0
3 years ago
Read 2 more answers
Solve for z.<br> 12 = 15 ( z - 1/5 )
bija089 [108]

Answer:

1=z

Step-by-step explanation:

Multiply 15 to the parenthesis.  

12=15z-15/5

12=15z-3

Add 3 to both sides

15=15z

Simplify

1=z

5 0
3 years ago
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