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svetlana [45]
3 years ago
8

Can someone can help me please

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0
The answer is 63 nickels so C
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Need help fast with this question fourty points and branliest!!
Colt1911 [192]

You can use SAS, or Side Angle Side. Because BC equals EC and AC equals DC, you can get two sides. Also, angle BCA and DCE have the same angle measurement, so you can conclude, using SAS, that BA equals to ED. Also, you can also prove that these two triangles are congruent and that all of the angles are the same as well because all of the side lengths are equal.


8 0
4 years ago
Read 2 more answers
Which fraction is equivalent?<br> 1/6 5/30 6/30
gogolik [260]
1/6 and 5/30 are equivalent. They are equivalent because is you divide 5/30 by 5, you will get 1/6.
Hope this helps!
8 0
4 years ago
Read 2 more answers
How can you solve standard form and intercept form?
laiz [17]

Answer:

The standard form of such an equation is Ax + By + C = 0 or Ax + By = C. When you rearrange this equation to get y by itself on the left side, it takes the form y = mx +b. This is called slope intercept form because m is equal to the slope of the line, and b is the value of y when x = 0, which makes it the y-intercept.

Step-by-step explanation:

8 0
3 years ago
Round 694,553 to the nearest hundred thousand.​
docker41 [41]

Answer:

pretty sure its 700,000

4 0
3 years ago
Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio
Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0
3 years ago
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