All categories

1 year ago

What is the quotient of the fractions below? 4/7 divided by 7/5

Mathematics

1 answer:

Blizzard [7]1 year ago

8 0

The quotient of the fraction is 20/49.

<h3>What is Fraction?</h3>

Fractions are represented as a numerical value, which defines a part of a whole.

Here, the given fractions are:

4/7 and 7/5

Now, according to question

4/7 ÷ 7/5

= 4/7 × 5/7

= (4×5)/(7×7)

= 20/49

Thus, the quotient of the fraction is 20/49.

Learn more about Fraction from:

brainly.com/question/10354322

#SPJ1

You might be interested in

A basketball player is 7 feet tall and releases the ball when his hands are 8 feet into the air at a velocity of 12 feet per sec

Triss [41]

Answer: 5x3

Step-by-step explanation: 15

3 0

3 years ago

en la librería habían 680 libros para el comienzo de clase pidieron a la editorial 125 más Cuántos libros hay ahora en total par

AnnyKZ [126]

Answer:

Que? No se.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Round 43.7575 to the nearest thousandth. a) 43.700 b) 43.758 c) 43.750 d) 43.757

aleksandr82 [10.1K]

Answer:

B) 43.758

Step-by-step explanation:

Starting from the right side of the decimal point, the places are:

tenths

hundredths

thousands

Each time, you add a zero to the previous number (10 to 100 to 1000, etc), therefore the third decimal would be the thousandths place. If the next figure is a 5 or above, you round up, to the next decimal.

6 0

2 years ago

Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.

galben [10]

Answer:

The interval of increase of g(x) is $(-6,+\infty)$ .

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be $g(x) = 190 + 8 \cdot x^{3} + x^{4}$ , the first derivative of the function is:

$g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}$

$g'(x) = 4 \cdot x^{2}\cdot (6+x)$

The following condition must be met to define the interval of increase:

$4\cdot x^{2} \cdot (x+6) > 0$

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

$x + 6 > 0$