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3 years ago

Which fraction is equivalent? 1/6 5/30 6/30

Mathematics

2 answers:

gogolik [260]3 years ago

8 0

1/6 and 5/30 are equivalent. They are equivalent because is you divide 5/30 by 5, you will get 1/6.
Hope this helps!

Andreas93 [3]3 years ago

7 0

1/6 and 5/30 are both equivalent, this is because when you simplify 5/30 it come out to 1/6.

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2) Evaluate the given numerical expression. A) 9 B) 12 C) 14 D) 21

eduard

Answer:

$\boxed{\sf{14}}$

Step-by-step explanation:

$\boxed{\underline{\text{ORDER OF OPERATIONS:}}}$

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

PEMDAS

Parentheses
Exponents
Multiply
Divide
Add
Subtract

BODMAS

Brackets
Order
Divide
Add
Subtract

First, do parentheses.

3+6*(5+4)÷3-7

(5+4)=9

$\Longrightarrow: \sf{3+6* 9\div 3-7}$

Do multiply and divide.

6*9=54

54/3=18

Then, rewrite the problem down.

$\Longrightarrow: \sf{3+18-7}$

Add.

$\sf{3+18=21}$

$\sf{21-7=\boxed{\sf{14}}$

$\Longrightarrow: \boxed{\sf{14}}$

Therefore, the correct answer is "C. 14".

I hope this helps, let me know if you have any questions.

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2 years ago

Hunter is bisecting the angle shown. When drawing the arcs centered on points P and Q, why must he keep the compass the same wid

S_A_V [24]

Answer:

The arcs are drawn to find a point on the bisecting ray. If the arcs are the same width, it makes sure that they are equidistant from the points on the rays of the angle. This causes the point to be on the bisecting ray.

Step-by-step explanation:

Bisection of an angle implies dividing the angle into two equal parts. The ray that divides the angle is called a bisector.

The hunter should use the same radius or width to draw the two arcs, using points P and Q as the center interchangeably, so that they would intersect at an equidistant point to P and Q. The point of intersection lies on the bisecting ray of the angle.

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3 years ago

A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur

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Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

$V=LWH$