100 factorial is 1*2*3*......*100
Number of multiples of 2 less than 100 = 49
Number of multiples of 3 less than 100 = 33
We are double counting those that are multiples of 2 and 3 (or 6)
Number of multiples of 6 less than 100 = 16
49+33-16 =66
There are 66 factors that are multiples or 2 or 3
As we know 1/4 mile = 402.336 m
So, 402.336 ÷ 4 = 100.584 m
100.584 m = 0.0625 mile or 1/16 mile
Hope it helps you
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Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Step-by-step explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.
Answer:
It's a perfect cube, but not a perfect square.
Step-by-step explanation:
2^3 = 8, meaning 8 is a perfect cube. But since 2^2 = 4 and 3^2 = 9, and 8 is in between, 8 is not a perfect square.
I hope this helped.
Answer:
The correct option is (d)-He wrote commutative instead of associative in Step 2.
Step-by-step explanation:
Commutative property: 
Associative property:
Now consider the provided expression.
(6.2 − 1.6) − 4.4 + 7.8
Step 1
(6.2 − 1.6) − 4.4 + 7.8
Step 2 Use Associative property
6.2 + (−1.6 − 4.4) + 7.8
Step 3: Simplify
6.2 − 6 + 7.8
Step 4: Use commutative property
14 − 6
Step 5: Simplify
14 − 6 = 8
Hence, the wrong step is step 2. He wrote commutative instead of associative in Step 2.
Therefore, the correct option is (d)-He wrote commutative instead of associative in Step 2.