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ivanzaharov [21]
3 years ago
6

How do i solve this question

20%20-%2080t%20%2B%201200%29" id="TexFormula1" title="h = \frac{1}{16} ( {t}^{2} - 80t + 1200)" alt="h = \frac{1}{16} ( {t}^{2} - 80t + 1200)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
sattari [20]3 years ago
7 0

Answer:

h=1/16t^2-5t+75

Step-by-step explanation:

solve for h

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Solve for y. 2/3+y−1/9=7/9 Enter your answer in the box 
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Sketch the region that is common to the graphs of x ≥ 2,
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a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

#SPJ1

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1 year ago
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Each girl ate 1/4 hope this helps
6 0
2 years ago
Read 2 more answers
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